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-7a^2+19a+6=0
a = -7; b = 19; c = +6;
Δ = b2-4ac
Δ = 192-4·(-7)·6
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-23}{2*-7}=\frac{-42}{-14} =+3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+23}{2*-7}=\frac{4}{-14} =-2/7 $
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